modified on 20 November 2010 at 17:16 ••• 2,850 views

Lösungen Kapitel 4

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(Created page with "==Aufgabe 4.1:== Kugelvolumen= <math>\frac{4}{3}\pi r^3</math> Bei 200nm/500nm Durchmesser <math>\longrightarrow V= 419 nm^3/ 1047nm^3</math> <math>pH=5=-log(\frac{[H]}{mol})...")
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Revision as of 12:17, 7 November 2010

Aufgabe 4.1:

Kugelvolumen= LaTeX: \frac{4}{3}\pi r^3

Bei 200nm/500nm Durchmesser LaTeX: \longrightarrow V= 419 nm^3/ 1047nm^3

LaTeX: pH=5=-log(\frac{[H]}{mol}) \longrightarrow [H]=10^{-5}\frac{mol}{l}

LaTeX: N=V*[OH]= Unter 1(?)