modified on 20 June 2014 at 08:37 ••• 129 views

User:AlbertineStorrs

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Ignition coil + E shocker I tried to run an ignition Test equipment rentals coil with the E shocker grad... ... doesn't work. But why? While there on the home page the circuit with the capacitors + rectifier but why not go with the shocker alone? Too little power? E shocker was operated with 9V battery. Hope not ever asked. because 1 the frequency of the e shocker is too low and 2. only provide the necessary power for the ignition coil the condenser (and also the necessary frequency generated). NO frequency is generated by a capacitor! the funzt with the shocker of course not, da saeine voltage at load immediately breaks (too little power)... that's why they kondis: which are charged, and then pulse wise in the ZS unloaded. Provide the Kondis of course for a short time an extremely high power, therefore a Flash come out back then I that yesterday in bed even suspicious made me, with "Capacitor generates correct frequency". But not damage the high power the windings of the coil? Because if the capacitor to discharge then yes the power for a short time (beautician short time) against infinity goes, or because I wouldn't be au already for the next question though which do little with the ignition coil has. How can I calculate the short-circuit current which arises when a capacitor at a short circuit discharge? I think you can conjure up not infinitely many electrons, therefore there will be a border type, or am I wrong there? Of course, there is a limit but yes I = Q/t is the formula and we have given the charge. Now is only the issue of time. How long is a short circuit? Because under the fraction bar, anything goes to zero, the result against infinity